焦点为(1,0)设AB方程为x＝my+1（m不存在时直线与抛物线仅一交点,不成立）A(x1,y1)(x2,y2)代入抛物线方程,y^2=4(my+1)=4my+4于是由韦达定理,y1+y2=4m,y1y2=-4而S△AOB＝S△AOF+S△BOF＝1/2*OF|y1-y2|,而OF＝1于是S＝1...