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3道因式分解,
(1)(x^2-5)^2+8(5-x^2)+16
(2)a^2-b^2-4a+4
(3)2xy-x^2-y^2+1
人气:311 ℃ 时间:2020-02-03 15:20:54
解答
1=(X^2-5)^2-8(X^2-5)+16
=(X^2-5-4)^2
=(X^2-9)^2
2=(a^2-4a-4)-b^2
=(a-2)^2-b^2
=(a-2+b)(a-2-b)
3=X^2+Y^2-2XY-1
=-[(x-y)²-1]
=-(x-y-1)(x-y+1)
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