(a²+4a+4)+(a+b)²+10(a+b)+25=0
(a+2)²+(a+b+5)²=0
所以a+2=0,a+b+5=0
a=-2,b=-3
原式=3a²-a²b+(3ab-a²b)+4a²-2ab
=7a²-a²b+3ab-a²b-2ab
=7a²-2a²b+ab
=28+24+6
=58