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x+y/2=2y-z/3=2 x-3y+z=10
人气:362 ℃ 时间:2020-06-14 10:39:09
解答
x+y/2=2y-z/3=2
*6后=3x+3y=4y-2z=12
得x+y=4①
2y-z=6②
①-②=x-y+z=-2③
x-3y+z=10 ④
④-③=-2y=12
y=-6
代入x+y/2=2得x=10
代入2y-z/3=2得z=-18
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