已知a的平方+b的平方-6a-8b+25=0,求2a+3b的值
人气：253 ℃ 时间：2020-03-29 18:24:36
解答
a^2+b^2-6a-8b+25=0
[a-3]^2+[b-4]^2=0
a-3=0===>a=3
b-4=0===>b=4
2a+3b=2*3+3*4=6+12=18
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