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求值域!y=x^2-3x+5 x∈(-3,1)
人气:226 ℃ 时间:2020-04-06 12:15:25
解答
y=x^2-3x+5=x^2-2*3/2*x+(3/2)^2-(3/2)^2+5=(x-3/2)^2-9/4+5 =(x-3/2)^2+11/4 x∈(-3,1)即-3
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