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数学
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x²-4x+y²+6y+(√2-3)+13=0 ,求(xy)²=?
人气:273 ℃ 时间:2019-10-19 18:31:14
解答
x²-4x+y²+6y+√(z-3)+13=0
x²-4x+4+y²+6y+9+√(z-3)=0
(x-2)²+(y+3)²+√(z-3)=0
因此x=2,y=-3,z=3
(xy)^z = (2*(-3))^3 = -216
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