已知x,y满足x²+y²-4x-6y+13=0,求(- y/x^3)^3÷(- 1/xy)^4.(x/y^2)^2的值
人气:499 ℃ 时间:2019-08-18 07:00:58
解答
x²+y²-4x-6y+13=0x²-4x+4+y²-6y+9=0(x-2)²+(y-3)²=0x=2 y=3 (- y/x^3)^3÷(- 1/xy)^4.(x/y^2)^2=-y^3/x^9 * x^4y^4*x^2/y^4=-y^3/x^3=-(y/x)³=-(3/2)³=-27/8如果本题有...
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