令t=x-10/3,带入原式消去x^2项,化简得：x^3-91x/27-2945/729=0构造x=u+v,显然x^3=(u+v)^3=u^3+v^3+3uv(u+v)=3uvx+u^3+v^3,即x^3-3uvx-(u^3+v^3)=0对比两个一元三次方程,得：-3uv=-91/27,-(u^3+v^3)=-2945/729变形得...