求x(arctanx)的不定积分
人气:352 ℃ 时间:2020-04-06 00:40:53
解答
∫x(arctanx)dx
=(1/2)∫ (arctanx)d(x^2)
= (1/2)x^2(arctanx) -(1/2)∫ x^2 (1/(1+x^2) dx
= (1/2)x^2(arctanx) - (1/2)∫ dx+ (1/2)∫ 1/(1+x^2) dx
= (1/2)x^2(arctanx) - (1/2)x + (1/2) arctanx + C
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