解f(x)=√3sinx/2cosx/2+cos²x/2-1/2=√3/2sinx+1/2cox=sinxcosπ/6+cosxsinπ/6=sin(x+π/6)当-π/2+2kπ≤x+π/6≤π/2+2kπ即-2π/3+2kπ≤π/3+2kπ时f(x)是增函数∴单调递增区间为[2kπ-2π/3,2kπ+π/3](...