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化简[(1-lg5)^2+lg2乘lg5]/lg8
人气:279 ℃ 时间:2020-06-10 11:35:02
解答
[(1-lg5)^2+lg2乘lg5]/lg8
=[(lg10-lg5)²+lg2*lg5]/lg2³
=(lg²2+lg2*lg5)/(3lg2)
=lg2(lg2+lg5)/(3lg2)
=lg2/(3lg2)
=1/3
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