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2(x+3)²=x²-9 解方程
人气:254 ℃ 时间:2020-03-29 02:46:26
解答
2(x+3)²=x²-9
2(x²+6x+9)=x²-9
2x²+12x+18-x²+9=0
x²+12x+27=0
(x+3)(x+9)=0
x1=-3,x2=-9用因式分解法2(x+3)²=x²-92(x+3)²=(x+3)(x-3)2(x+3)²-(x+3)(x-3)=0(x+3)[2(x+3)-(x-3)]=0(x+3)(x+9)=0x1=-3,x2=-9
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