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cos^2x+cos^2(x+120°)+cos^2(x+240°)
人气:400 ℃ 时间:2020-04-18 16:55:23
解答
原式=cos²x+{-cos[180-(x+120)]}²+{-cos[180-(x+240)]}²
=cos²x+cos²(60-x)+cos²(60+x)
=cos²x+(cos60cosx+sin60sinx)²+(cos60cosx-sin60sinx)²
=cos²x+(1/2cosx+√3/2sinx)²+(1/2cosx-√3/2sinx)²
=cos²x+1/4cos²x+√3/2sinxcosx+3/4sin²x+1/4cos²x-√3/2sinxcosx+3/4sin²x
=3/2*cos²x+3/2sin²x
=3/2(sin²x+cos²x)
=3/2
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