(y-1)/2=sin[(x-1)/(x+1)](x-1)/(x+1)=arcsin[(y-1)/2]1-2/(x+1)=arcsin[(y-1)/2]2/(x+1)=1-arcsin[(y-1)/2]x+1=2/{1-arcsin[(y-1)/2]}x=2/{1-arcsin[(y-1)/2]}-1所以反函数就是:y=2/{1-arcsin[(x-1)/2]}-1