(2014x)²-2013*2015x-1=(2014²x+1)(x-1)方法设2014²=a2013*2015=(2014-1)(2014+1)=a-1所以原式=ax²-(a-1)x-1=(ax²-ax)+(x-1)=ax(x-1)+(x-1)=(ax+1)(x-1)=(2014²x+1)(x-1)���