郭敦顒回答：x≠0,0＜x≤2,x→0时,1/ln(x+1) →+∞,√（4－x²）→2,y→+∞；x=2时,1/ln(x+1)=0.91024,√（4－x²）=0,y=1/ln(x+1)+√（4－x²）=0.91024,∴y=1/ln(x+1)+√（4－x²）的值域是：[0.9...