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已知(sina+cosa)/(sina-cosa)=2,则:(3sina+cosa)/(2sina+3cosa)=?sin^2a-2sinacosa+1=?
人气:265 ℃ 时间:2019-10-10 03:46:31
解答
(sina+cosa)/(sina-cosa)=2 => sina = 3 cosa,tana=3,(seca)^2 = 10
(3sina+cosa)/(2sina+3cosa) = (3 tana +1)/(2 tana+3) = 10/9
sin^2a-2sinacosa+1 = (cosa)^2 [ (tana)^2 - 2 tana + (seca)^2 ]
= (1/10) ( 9-6+10) = 13/10
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