∵已知单项0.25x的b次方y的c次方与单项式_0.125x的m次方y的(2n-1)次方的和为0.625ax∴0.25x^by^c＋﹙﹣0.125x^my^(2n-1)﹚＝0.625ax∴0.25－0.125＝0.625a,b＝m＝1,c＝2n－1＝0a＝0.2,b=m=1,c=0,n=0.5bc-m+n/a＝1×0...