> 其他 >
微分方程x*dy/dx+y=3
它的通解是Y=C/x+3吗,我把通解带进去求等是不相等,
xdy + (y-3)dx = 0
到xd(y-3) + (y-3)dx = 0不懂,xd(y-3) 怎么变过去的呢
人气:218 ℃ 时间:2020-01-14 13:54:05
解答
x*dy/dx+y=3两边同时乘以dxxdy + (y-3)dx = 0soxd(y-3) + (y-3)dx = 0sod[x(y-3)] = 0sox(y-3)=C C is a constantsoy=C/x+3检验:x*dy/dx+y=x*(-C/x^2) + C/x+3 = -C/x + C/x+3 = 3,满足原方程.
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版