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若|x-3|+(y+2)=0,则(x-y+4xy/x-y)(x+y-4xy/x+y)的值是
人气:451 ℃ 时间:2020-02-08 21:19:47
解答
由已知得:X-3=0,Y+2=0 解得:X=3,Y=-2,∴原式=[(X-Y)^2+4XY)]/(X-Y)][(X+Y)^2-4XY]/(X+Y) =(X+Y)^2(X-Y)^2/[(X-Y)(X+Y)] =(X+Y)(X-Y) =X^2-Y^2 =9-4 =5.
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