由已知得：
X-3=0,
Y+2=0
解得：X=3,Y=-2,
∴原式=［(X-Y)^2+4XY)］/(X-Y)］［(X+Y)^2-4XY］/(X+Y)
=(X+Y)^2(X-Y)^2/［(X-Y)(X+Y)］
=(X+Y)(X-Y)
=X^2-Y^2
=9-4
=5.