若|x-3|+(y+2)²=0,则(x-y+4xy/x-y)(x+y-4xy/x+y)的值是
人气:113 ℃ 时间:2020-04-04 17:43:26
解答
由已知得:
X-3=0,
Y+2=0
解得:X=3,Y=-2,
∴原式=[(X-Y)^2+4XY)]/(X-Y)][(X+Y)^2-4XY]/(X+Y)
=(X+Y)^2(X-Y)^2/[(X-Y)(X+Y)]
=(X+Y)(X-Y)
=X^2-Y^2
=9-4
=5.
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