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求函数y=cos 2x+sin x的值域
人气:197 ℃ 时间:2019-10-09 11:02:13
解答
y=1-2*(sinx)^2+sinx
=-2*(sinx-1/4)^2+9/8
而-25/8≤-2*(sinx-1/4)^2≤0,所以
-2≤y≤9/8
所以函数y=cos 2x+sin x的值域:[-2,9/8]
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