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计算:sin²30°+cos²45°+根号2sin60°×tan45°
(cos²30°+cos²60°)/(tan60°×cos30°)+tan60°
人气:148 ℃ 时间:2020-02-04 17:11:19
解答
sin²30°+cos²45°+根号2sin60°×tan45°
=(1/2)²+(√2/2)²+√2×√3/2×1
=1/4+1/2+√6/2
=3/4+√6/2
(cos²30°+cos²60°)/(tan60°×cos30°)+tan60°
=( 3/4+1/4)/(√3×√3/2)+√3
=2/3+√3
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