答：∫[(x-4)/(x^2-3x+2)]dx=∫{(x-4)/[(x-2)(x-1)]}dx=∫{(x-4)[1/(x-2)-1/(x-1)]}dx=∫[(x-4)/(x-2)]dx-∫[(x-4)/(x-1)]dx=∫[1-2/(x-2)]dx-∫[1-3/(x-1)]dx=x-2ln|x-2|-x+3ln|x-1|+C=3ln|x-1|-2ln|x-2|+C...