利用三角万能公式可得
1/cos2α+tan2α
=(1+tan^2α)/(1-tan^2α)+2tanα/(1-tan^2α)
=(1+tanα)^2/[(1-tanα)(1+tanα)]
=(1+tanα)/(1-tanα)
=(tanπ/4+tanα)/(1-taπ/4tanα)
=tan(π/4+α)
=2010