设此4个数依次为a/q,a,5-a,(5-a)q则(5-a)/a=q,(q+1)a=5 a=5/(q+1)这4个数依次变为5/[q(q+1)],5/(q+1),5q/(q+1),5q²/(q+1).[5/q(q+1)][5/(q+1)][5q/(q+1)][5q²/(q+1)]=16整理,得q²/[(q+1)⁴]=16/...