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(x+y)(x2-xy+y2)
人气:497 ℃ 时间:2020-01-19 22:48:12
解答
原式=(x+y)[(x-y)²+xy]
=(x²-y²)(x-y)+x²y+xy²
=x³-x²y-xy²+y³+x²y+xy²(-x²y-xy²+x²y+xy²抵消掉)
=x³+y³
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