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2005³+2005²-2006分之2005³-2×2005²-2003(因式分解) x四次y四次+4(分解因式)
人气:257 ℃ 时间:2019-10-11 00:52:22
解答
(2005^3-2×2005^2-2003)/(2005^3+2005^2-2006)=(2005^2×(2005-2)-2003)/(2005^2×(2005+1)-2006)=(2005^2×2003-2003)/(2005^2×2006-2006)=(2003×(2005^2-1))/(2006×(2005^2-1))=2003/2006
x^4 ·y^4+4
=(x²y²+2)² - 4x²y²
=(x²y²+2)² - (2xy)²
=(x²y²+2+2xy)(x²y²+2-2xy)
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