f(x)=√3sin(wx+b)-cos(wx+b)f(x)=2[sin(wx+b)cosπ/6-cos(wx+b)sinπ/6]f(x)=2sin(wx+b-π/6)因为f（x）为偶函数,所以：f(-x)=f(x),即：2sin(-wx+b-π/6)=2sin(wx+b-π/6);所以：b-π/6=π/6-b+π,得到：b=2π/3.又...