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计算:1-[a- 1/(1-a)]²÷[(a²-a+1)/(a²-2a+1)]
人气:439 ℃ 时间:2020-02-06 10:35:03
解答
1-[a- 1/(1-a)]²÷[(a²-a+1)/(a²-2a+1)]
=1-[a(1-a)/(1-a)-1/(1-a)]²÷[(a²-a+1)/(a-1)²]
=1-(a²-a+1)²/(a-1)²×(a-1)²/(a²-a+1)
=1-(a²-a+1)
=-a²+a
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