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求证:(cosA/(tanA/2-cotA/2))=-1/2*sinA
人气:412 ℃ 时间:2020-02-05 22:06:38
解答
tan(A/2)-cot(A/2)
=sin(A/2)/cos(A/2)-cos(A/2)/sin(A/2)
=[sin²(A/2)-cos²(A/2)]/cos(A/2)sin(A/2)
=-cosA/(1/2sinA)
=-2cosA/sinA
所以:
等式左边=cosA/[tan(A/2)-cot(A/2)]
=cosA/(-2cosA/sinA)
=-1/2*sinA
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