甲乙两车同时从A、B两城相向而行,在距中点40千米处相遇,已知甲车是乙车速度的3倍,求AB两城距离.【列算式,清楚些】
人气:303 ℃ 时间:2020-03-30 09:45:51
解答
如果一样的速度,应该在中点相遇有了速度差,就不能在中点了甲的路程减去乙的路程就是2倍的乙的路程,而这个差就是2倍的40千米也就是80千米那么总路程就是120+40=160千米这是方程设乙车的速度为x,AB两地的距离为y千米则...
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