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一道三元一次数学题
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{3x-y+z=4
{2x+3y-z=12
{x+y+z=6
人气:124 ℃ 时间:2020-03-19 04:33:38
解答
3x-y+z=4-----1式2x+3y-z=12-----2式x+y+z=6-----3式1式 + 3式,得:4x + 2z = 10 ---->2x + z = 5------4式3式 * 3 - 2式,得:x + 4z = 6 -------5式5式 * 2 - 4式,得:7z = 7 -----> z = 1将z = 1代入3式:x + y = 5 ------6式将z = 1代入1式:3x - y = 3 ------7式6式 + 7式,得:4x = 8 ------>x = 2将x = 2代入6式:2 + y = 5----->y = 3所以:x = 2;y = 3;z = 1;
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