> 数学 >
求函数y=log2底sin(2x+π\4)的单调递增区间和单调递减区间
人气:313 ℃ 时间:2020-03-29 15:01:29
解答
y=log2底sin(2x+π/4)有意义
sin(2x+π/4)>0
单增区间为
2kπ<2x+π/4<2kπ+π/2
2kπ-π/4<2x<2kπ+π/2-π/4
kπ-π/8<x<kπ+π/8
单减区间为
2kπ+π/2<2x+π/4<2kπ+π
2kπ+π/2-π/4<2x<2kπ+π-π/4
kπ+π/4<x<kπ+3π/8
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版