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先化简再求值[(x+y)2-(x+y)(x+3y)-4y2]÷2y,其中x=-2,y=
1
2
人气:102 ℃ 时间:2020-02-03 11:12:06
解答
[(x+y)2-(x+y)(x+3y)-4y2]÷2y,
=[x2+2xy+y2-x2-3xy-xy-3y2-4y2]÷2y
=(-2xy-6y2)÷2y
=-x-3y,
当x=-2,y=
1
2
时,
原式=-(-2)-3×
1
2

=
1
2
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