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高数极限lim[1-cosx(cos2x)^(1/2)]/x^2求解,快
人气:484 ℃ 时间:2019-10-04 12:48:17
解答
lim1-cosx(cos2x)^(1/2)/x^2=lim1-cosx(cos2x)^(1/2)*1+cosx(cos2x)^(1/2)/{x^21+cosx(cos2x)^(1/2)}=lim1-cosx^2cos2x/{x^21+cosx(cos2x)^(1/2)}=lim1-cosx^2(cosx^2-sinx^2)/{x^21+cosx(cos2x)^(1/2)}=limcosx^2+s...
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