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已知x+y=1,xy=3/16,求x³y-2x²y²+xy³
人气:396 ℃ 时间:2019-11-12 22:32:46
解答
x³y-2x²y²+xy³
=xy(x²-2xy+y²)
=xy[(x+y)²-4xy]
=3/16*(1²-4*3/16)
=3/64
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