(ab)'=a'b+ab'
f(x)=(x+1)²(x-1)³
f'(x)=2(x+1)(x-1)³+(x+1)²3(x-1)²
f'(x)=(x+1)(x-1)²[2（x-1）+3(x+1)]
f'(x)=(x+1)(x-1)²(5x+1)你题目看错了吧，是x-1的2分之3次方？手机用户，请在客户端右上角评价点“满意”即可？