> 数学 >
z=(e^u)sinv,u=xy^2,v=x-y,求dz
人气:380 ℃ 时间:2020-06-14 06:15:26
解答
dz=(e^u)sinvdu+(e^u)cosvdv
=(e^u)sinv[y²dx+2xydy]+(e^u)cosv[dx-dy]
=e^(xy²)[y²sin(x-y)+cos(x-y)]dx+e^(xy²)[2xysin(x-y)-cos(x-y)]dy
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版