4y^4-4x^3+0.2x^2y^2+xy^3-1/5x^2y^2-4y^4-x^3y,其中x=-2,y=0.3.
人气:300 ℃ 时间:2019-08-20 07:12:53
解答
4y^4-4x^3+0.2x^2y^2+xy^3-1/5x^2y^2-4y^4-x^3y
=-4x^3+xy^3-x^3y
=-4×(-2)^3+(-2)×0.3^3-(-2)^3×0.3
=32-0.054+2.4
=34.346
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