已知函数f（x）=ln
(-3x）+1，则f（lg2）+f
(lg)=（ ）
A. -1
B. 0
C. 1
D. 2
人气：486 ℃ 时间：2019-08-21 15:51:47
解答
函数
f(x)=ln(-3x)+1，
则
f(lg2)+f(lg)=f（lg2）+f（-lg2）
=
ln(-3lg2)+1+
ln(+3lg2)+1=
ln()+1+
ln(+3lg2)+1=
-ln(+3lg2)+1+
ln(+3lg2)+1=2．
故选：D．
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