[(a^2*b)^2m-(ab^2)^2m-1]/a^m*b^m-1
=[a^4mb^2m-a^(2m-1)b^(4m-2)]/a^mb^(m-1)
=a&3mb^(m+1)-a^(m-1)b^(3m-1)
[4(x-2)+12(x+2)(x-2)-8(x-2)(x-1)]/4(x-2)
=1+3x+6-2x+2
=x+9
[(x+2y)(x-2y)-(2x-y)^2+(3x-y)(2x-5y)]/(-1/3x)
=(x²-4y²-4x²+4xy-y²+6x²-17xy+5y²)/(-1/3x)
=(3x²-13xy)/(-1/3x)
=-9x+39y
解方程:3(6x-5)-4(x+2)=5(x-2)-x
18x-15-4x-8=5x-10-x
14x-4x=-10+23
10x=13
x=13/10
x=1.3
2(2y+1)^2-8(y+4)(y-4)=30
8y²+8y+2-8y²+128=30
8y=30-130
8y=100
y=12.5