>
数学
>
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
人气:464 ℃ 时间:2020-03-20 16:53:50
解答
cos1°+cos2°+cos3°+...+cos178°+cos179°
=(cos1°+cos179°)+(cos2°+cos178°)+……+(cos89°+cos91°)+cos90°
=(cos1°-cos1°)+(cos2°-cos2°)+……+(cos89°-cos89°)+cos90°
=cos90°
=0
推荐
cos1°+cos2°+cos3°+...+cos179°化简
cos1°+cos2°+cos3°+……cos180°=_______
cos1+cos2+cos3+.+cos180的值
求cos1º+cos2º+cos3º+……+cos178º+cos179º的值
cos1°+cos2°+cos3°.+co180°=?
Should we always share pleasure with our friends?Why?
You are are pure lovely of girl,I will make an effort to protect you!
求后街男孩i want it that way中文翻译
猜你喜欢
Do you think if he ___(have) a good enting habit?my father‘s eating habits( habit
用配方法解下列方程 2x²+bx+a=0解得x-3/2=±根号15/2 求a b值
一元一次方程的特征是什么
为什么n-1+n-2+...+1=n(n-1)/2
集合[a,b]的子集的个数有多少?
呼吸链是什么
there___(be) a map of China on the wall
我需要50道初一解方程 不要应用题是解方程计算题
© 2026 79432.Com All Rights Reserved.
电脑版
|
手机版