函数y=2sin(2x+π/3)+sin(2x-π/3)的最小正周期
人气：396 ℃ 时间：2019-11-11 22:31:24
解答
y=2sin(2x+π/3)+sin(2x-π/3)=sin(2x+π/3)+sin(2x-π/3)+sin(2x+π/3)=sin2x+sin(2x+π/3)=3/2sin2x+√3/2cos2x=√3sin(2x+π/6),所以最小正周期为π
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