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函数y=2sin(2x+π/3)+sin(2x-π/3)的最小正周期
人气:180 ℃ 时间:2019-10-17 01:56:04
解答
y=2sin(2x+π/3)+sin(2x-π/3)
=2(sin2xcos派/3+cos2xsin派/3)+sin2xcos派/3-cos2xsin派/3
=3sin2xcos派/3+cos2xsin派/3
=3/2sin2x+根号3/2cos2x
从这里即可看出,最小正周期为“派”.
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