求一个数学题的通项公式
写出2,4,7,11,16的通项公式(n≧2)答案尽可能详细点
人气:113 ℃ 时间:2019-10-19 03:38:51
解答
2,2+2,4+3,7+4,11+5 .
A1=2
A2=A1+2
则An项=A(n-1)项+n
A3=A2+3=(A1+2)+3
A4=A3+4=(A1+2)+3+4
An=A1+n+(n-1)+(n-2)+……+2 =A1+(n-1)*(n+2)/2=(n^2+n+2)/2
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