F 浮＝ρ液*g*V排＝m排液*g=0.004kg*10=0.04N,则该木块酒精中受到的浮力是0.04N.
把木块放在水里,还是漂浮,浮力=重力=0.04N.
F 浮＝ρ液*g*V排＝m排液*g则,溢出水是0.04N/1N/kg=0.04kg.