i³(i+1)/(i-1)
=-i*i
=1能麻烦把答案写具体些吗？非常感谢i³=i²*i=-i(i+1)/(i-1),上下同乘i+1(i+1)*(i+1)/(-2)=(i²+1+2i)/(-2)=2i/(-2)=-i那么就有i³(i+1)/(i-1)=-i*i=1