若x=√2,求代数式[(x^2-2x+4)/(√x^2-4x+4)]/[(x^3+8)/(x^2-4)]*[|6-x|/(x^2-_数学解答

若x=√2,求代数式[(x^2-2x+4)/(√x^2-4x+4)]/[(x^3+8)/(x^2-4)]*[|6-x|/(x^2-5x-6)-[1/(x^2-x+1)]^-1的值

人气：342 ℃　时间：2020-03-28 03:07:58

解答

[(x^2-2x+4)/(√x^2-4x+4)]/[(x^3+8)/(x^2-4)]*[|6-x|/(x^2-5x-6)- [1/(x^2-x+1)]^-1=[(x^2-2x+4)/|x-2|]/[(x^3+8)/(x^2-4)]*[|6-x|/(x-6)(x+1)-(x^2- x+1)=(x^2-2x+4)/(x-2)×(x-2)(x+2)/(x^3+8)[(6-x)/(x-6)(x+1)-...